Question

answer this plz. urgent​

Answer 1

Let ∆ ABC be the triangle with vertices A, B, and C respectively.

By distance formula,

d(A,B) = 4 .........(1)

d(B,C) = 2√2 ..........(2)

d(A,C) = 2√2 ...........(3)

From (1), (2), and (3), we get,

d(A,B)= d(B,C) is not equals to d(A,C)

So, two sides of the triangle are equal and one is odd.

Therefore the triangle is of isosceles triangle.......

Hope it helps u ......