Question

answer this questiion pls

Answer 1

$(a + b + c) = {9}^{2} \\ {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) = {9}^{2} \\ {a }^{2} + {b}^{2} + {c}^{?} + 2 \times 26 = 81 \\ {a}^{2} + {b}^{2} + {c}^{2} = 81 - 52 \\ {a}^{2} + {b}^{2} + {c}^{2} = 29$

Answer 2

Answer:

29

Step-by-step explanation:

Given, a+b+c=9 and ab+bc+ca=26.

We know, (a+b+c)2=a2+b2+c2+2ab+2bc+2ca

⇒(a+b+c)2=a2+b2+c2+2(ab+bc+ca).

Putting the values here, we get,

(9)2=a2+b2+c2+2(26)

⇒81=a2+b2+c2+52

⇒a2+b2+c2=81−52=29.