Math, asked by seema2778, 1 year ago

answer this question​

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Answered by kalyaniprasad8
1

Maximum buses= HCF(312,260,156)

312= 2³*3*13

260= 2²*5*13

156= 2²*3*13

HCF= 2²*13= 4*13= 52

Thus 52 buses are required

Answered by bhavya9816
0

Answer:

hi

the answer is right

bye

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