Math, asked by JobanJosan123, 1 year ago

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Answered by bhagatg433
1

Answer:

Ricky2015 Virtuoso

The smallest 3 digit no. = 100 is divisble by 5

=> 103 is the 1st 3 digit no. which will give rem. 3

The largest 3 digit no. = 999

999/5 gives rem. 4 => 998 will give rem. 3

this series is obviouly in AP , ( 103,108,111,...998 )

998 = 103 + ( n - 1 ) 5

=> n = 895/5 +1 = 180

So sum

= n/2 ( first term + last term )

= 180/2 ( 103 + 998 ) = 90 ( 1101 ) = 99090

hope it helps u


JobanJosan123: thanks
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