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Answer:
66 cm^3
Given,
Diameter of the model is 3 cm and length is 12 cm.Each cone has a height of 2 cm.
To Find,
Volume of air contained in the model.
Solution,
For Upper Conical portion,
Diameter of the model = 3 cm.
Radius = 3/2 = 1.5 cm
Height h = 2 cm
Volume = 1/3πr²h
==> 1/3 * π * (1.5)² * 2
==> 4.5/3 π
==> 1/5 π cm²
For Lower conical portion,
Volume = 1.5 π cm³
Radius R = 1.5 cm
Height H = 12 - (2 + 2) = 8 cm
Volume = πR²H
==> π(1.5)²*8
==> 18π cm³
We have to find Volume of model.
==> 1.5π + 1.5π + 18π
==> 21π
==> 21 * 22/7
==> 66 cm³
Result,
Volume of the air contained in the model = 66 cm³
#Hope my answer helped you.
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