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5
Answer:
0.0178 mol
Explanation:
0.1518 mol of NOBr is formed from 0.0518 mol of NO and 0.0518/2 = 0.0259 mol of BR2.
At equilibrium, Amount of NO = 0.087 – 0.0518 = 0.0352 mol
Amount of Br2 = 0.0437 – 0.0259 = 0.0178
Answered by
6
Nitric oxide reacts with Br2 and gives nitrosyl bromide as per reaction given below:
2NO (g) + Br2 (g) ⇌2NOBr (g)
When 0.087 mol of NO
and
0.0437 mol of Br2
are mixed in a closed container at constant temperature,
0.0518 mol of NOBr is obtained at equilibrium.
HOpe iT HelP YOu
Ram. Ram
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