Question

answer this question​

Answer 1

Answer:

$[b]=[ML^{-1}]\\\\\[[c]=[T^{2}]\\\\\[[D]=[T^{4}]$

Explanation:

Since, same physical quantities can be added or subtracted from each other, so, [c], [t²] and [√D] must have same dimensions.

∴ [c] = [T²]

and, [D] = [T⁴]

Also, dimensionally,

$[F] = \frac{[x^{2}b]}{[t^{2}]}\\\\\[[MLT^{-2}] =\frac{[L^{2}][b]}{[T^{2}]} \\\\\[[MLT^{-2}][T^{2}]=[L^{2}][b]\\\\\[[b]=[ML^{-1}]$