Physics, asked by anmolsinghrandhawa1, 1 year ago

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Answered by sbtgta125
0

Answer:

[b]=[ML^{-1}]\\\\\[[c]=[T^{2}]\\\\\[[D]=[T^{4}]

Explanation:

Since, same physical quantities can be added or subtracted from each other, so, [c], [t²] and [√D] must have same dimensions.

∴ [c] = [T²]

and, [D] = [T⁴]

Also, dimensionally,

[F] = \frac{[x^{2}b]}{[t^{2}]}\\\\\[[MLT^{-2}] =\frac{[L^{2}][b]}{[T^{2}]} \\\\\[[MLT^{-2}][T^{2}]=[L^{2}][b]\\\\\[[b]=[ML^{-1}]

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