Question

Answer this question

Answer 1

Given:

$a+b=17\\c+d=13\\a+c=19\\b+d=15$

To find:

a,b,c,d=?

Solution:

$\to a+b=17 ...(i)\\ \to c+d=13...(ii)\\\to a+c=19...(iii)\\ \to b+d=15...(iv)$

Solve equation (iv) and put the value in equation (i):

$\to b= 15-d$

$\to a +15-d =17\\\\\to a -d =17-15\\\\\to a -d = 2...(v)$

solve equation (v) and put the value into (ii):

$\to -d= 2-a\\\\\to d= a-2$

$\to c+a-2=13\\\\\to c+a=15\\\\\to a+c=15....(vi)$

The above-given equation is wrong because equation (iii) and equation (vi) were differed.