Question

answer this question ????​

Answer 1

Answer:

8,12,16 and 20

Step-by-step explanation:

Let the four parts be (a – 3d), (a – d), (a + d) and (a + 3d).

Then, sum = 56

⇒ (a – 3d) + (a – d) + (a + d) + (a + 3d) = 56

⇒ 4a = 56

⇒ a = 14

it is given that;

(a-3d) (a+3d)/(a+d) (a-d) =5/6

⇒a² -9d²/a² - d² = 5/6

⇒(14)² - 9d² / (14)² -d²= 5/6 (putting value of a)

⇒196-9d²/196-d²=5/6

⇒1176 - 54d²=980- 5d²

⇒1176-980=54d²-5d²

⇒ 49d²= 196

⇒d²= 4

⇒d=±2

thus, the four parts are a – 3d, a – d, a + d, a + 3d i.e., 8, 12, 16 and 20.