Question

answer this question ​

Answer 1

Answer:

$\: \huge \underline{ \bf{ \red{Answer}}}$

Your answer is 1

u can get solution in my attachment

Tq...

Answer 2

Option A is correct.

Explanation:-

Given that Sin 2A = Cos 3A

To find that Sin 5A = ?

Solution :-

$\sf \: Sin 2A \: = Cos 3A \\ \\ \sf \: Sin 2A = Sin (90 - 3A ) \: \: \: \: \{ \because Sin(90-A) = CosA \} \\ \\ \sf \: \cancel{Sin} \: 2A \: = \: \cancel{Sin} \: 90 - 3A \\ \\ \sf 2A = 90 - 3A \\ \\ \sf \: 2a + 3A = 90 \\ \\ \sf \: 5A = 90 \\ \\ \sf \: \purple{\boxed{ \bf \: a = 18}}$

Now, putting value of A in equation,

$\sf\implies \: Sin \: 5A \\ \sf \: = Sin \: 5(18) \: \\ \sf = Sin \: 90 \degree \\ \sf = 1$

Therefore, value of Sin 5A is 1.

Related Information:-

• Sin(90-A) = cosA

• Tan(90-A) = cotA

• Cos(90-A) = sinA

• Cot(90-A) = tanA

• Cosec(90-A) = secA

• Sec(90-A) = cosecA

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Sin 0° = 0

Sin 30° = 1/2

Sin 45° = 1/√2

Sin 60° = √3/2

Sin 90° = 1