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In the given figure,
DO is perpendicular to OE
Therefore angle DOE is 90 degrees
> DO is the bisector of angle AOC
Then angle DOA=angle DOC=x
>OE is the bisector of BOC
Angle COE=BOE=y
We know that angle DOE=90 degrees
That is angle DOC+ angle COE=90 degrees
That is x+y=90 degrees
In angle AOB,
AOB=angle (DOA+DOC+COE+EOB)
That is
Angle AOB=2x+2y
=2(x+y)
We know that x+y is 90 degrees
So angle AOB = 2(90)=180 degrees
Hence AOB is a straight line
Therefore points A,O&B lie are collinear
DO is perpendicular to OE
Therefore angle DOE is 90 degrees
> DO is the bisector of angle AOC
Then angle DOA=angle DOC=x
>OE is the bisector of BOC
Angle COE=BOE=y
We know that angle DOE=90 degrees
That is angle DOC+ angle COE=90 degrees
That is x+y=90 degrees
In angle AOB,
AOB=angle (DOA+DOC+COE+EOB)
That is
Angle AOB=2x+2y
=2(x+y)
We know that x+y is 90 degrees
So angle AOB = 2(90)=180 degrees
Hence AOB is a straight line
Therefore points A,O&B lie are collinear
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