Question

answer this question​

Answer 1

Answer:

• Given Polynomial : x² + 3x + k

• Zero =2

• If we substitute the zero then the polynomial will become zero. so, p(x) = 0

Value of k:-

${ \to{ \sf{p(x) = {x}^{2} + 3x + k }}} \\ \\ \: { \to{ \sf{p(2) = {2}^{2} + 3(2) + k = 0}}} \\ \\ { \sf{ \to{4 + 6 + k = 0}}} \\ \\ \to{ \sf{10 + k = 0}} \\ \\ { \sf{ \to{k = - 10}}}$

${ \therefore{ \sf{ \red{Option \: (b) \: is \: your \: answer}}}}$

Answer 2

Answer:

p(x) = x² + 3x +k

x = 2 [factor]

so , P(2)= (2)² +3(2) + k = 0

4 + 6 + k = 0

10 + k = 0

k = -10