Question

answer this question​

Answer 1

Answer:

sorry don't know the answer

Step-by-step explanation:

sorry!!

Answer 2

Answer:

ZOBC = 50°

ZOCB = 40

ZBCO = 90°

Step-by-step explanation:

Given.

In I gms ABC,

ZA = 80°

To Find.

ZOBC

LOCB

ZBCO

Solution.

In Parallelogram ABCD,

ZA = ZC [Opposite angles of a I gm are

equal]

ZB = ZD [Opposite angles of a Igm are

equal]

.. ZA = ZC = 80°

ZA+ ZD=180° [Co-interior angles]

80° + ZD = 180°

ZD = 100°

But ZB = ZD

.. ZB = 100°

ZC = 80°

Halving on both sides we get,

들 € = 80 2

.. ZOCB = 40° [OC is the angle bisector of ZC]

ZB = 100°

Halving on both sides we get,

B = 100 2

.. ZOBC ZB] = 50° [OB is the angle bisector of

In ABOC

ZOBC+ ZOCB+ ZBOC = 180°

50° +40° + ZBOC = 180°

90° + ZBOC = 180°

ZBOC = 180° - 90°

.. ZBOC = 90°

90+ BOC = 180°

ZBOC = 180° - 90°

.. ZBOC = 90°

Final answers

ZOCB = 40°

ZOBC = 50°

ZBOC = 90°

Step-by-step explanation:

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