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Answer:
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Step-by-step explanation:
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Answer:
ZOBC = 50°
ZOCB = 40
ZBCO = 90°
Step-by-step explanation:
Given.
In I gms ABC,
ZA = 80°
To Find.
ZOBC
LOCB
ZBCO
Solution.
In Parallelogram ABCD,
ZA = ZC [Opposite angles of a I gm are
equal]
ZB = ZD [Opposite angles of a Igm are
equal]
.. ZA = ZC = 80°
ZA+ ZD=180° [Co-interior angles]
80° + ZD = 180°
ZD = 100°
But ZB = ZD
.. ZB = 100°
ZC = 80°
Halving on both sides we get,
들 € = 80 2
.. ZOCB = 40° [OC is the angle bisector of ZC]
ZB = 100°
Halving on both sides we get,
B = 100 2
.. ZOBC ZB] = 50° [OB is the angle bisector of
In ABOC
ZOBC+ ZOCB+ ZBOC = 180°
50° +40° + ZBOC = 180°
90° + ZBOC = 180°
ZBOC = 180° - 90°
.. ZBOC = 90°
90+ BOC = 180°
ZBOC = 180° - 90°
.. ZBOC = 90°
Final answers
ZOCB = 40°
ZOBC = 50°
ZBOC = 90°
Step-by-step explanation:
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