Verify one kama minus one and 3 e are the the zeros of cubic polynomial x cube- 3 x square - X Plus 3
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Answer:
p(x) = x³- 3x²-x+3
p(-1) = (-1)³-3× (-1)² -(-1) +3
= -1 -3 +1+3
= 0
p(1) = 1×1³-3×1²-1+3
= 0
p(3) = 3³-3×3²-3+3
= 9-9-3+3
= 0
Hence verified that 1,-1,3 are the zeroes of cubic polynomial x³-3x²-x+3
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