Question

answer this question​

Answer 1

Answer:

a1 = p-1, a2 = p+3 and a3 = 3p-1

d = a2-a1 = a3-a2 ( Since they are in A.P.)

p+3-(p-1) = 3p-1-(p+3)

p+3-p+1 = 3p-1-p-3

4=2p-4

2p=4+4

2p=8

p=8/2

p=4

Hope it helps you!

Answer 2

Answer:

Now as we know that the p – 1, p + 3 and 3p – 1 are in AP. And according to the condition of AP if the terms a, b and c are in AP then the difference of the two consecutive terms must be equal and is known as the common difference i.e. b – a = c – b = common difference of the AP.