Math, asked by rasmiranjanjally9, 1 month ago


(x + 1) (x + 2)² (x + 3)³
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(x - 1)(x - 2)²(x - 3)³​

Answers

Answered by oswallaxmi19
0

Answer:

First try to solve (x3+1)(x2−1)2(x+2)3=0 then take all the numbers greater than the result. Now the equation can be splitt in to 3:

(x3+1)=0

(x2−1)2=0

(x+2)3=0

So the first equation gives us x=−1 , the second one x=±1 and the third gives us x=−2 . So this means when you make x any of these 3 values: −2 , −1 or 1 it will be 0, so any number ≥1 should be the answer.

Edit: After letting my computer plot this function, I can see now that it is below 0 for the numbers between −2 and −1 and greater or equal than 0 for all other values. I really thought it was the other away around

Answered by amrp8794
0

Answer:

First try to solve (x3+1)(x2−1)2(x+2)3=0 then take all the numbers greater than the result. Now the equation can be splitt in to 3:

(x3+1)=0

(x2−1)2=0

(x+2)3=0

So the first equation gives us x=−1 , the second one x=±1 and the third gives us x=−2 . So this means when you make x any of these 3 values: −2 , −1 or 1 it will be 0, so any number ≥1 should be the answer.

Edit: After letting my computer plot this function, I can see now that it is below 0 for the numbers between −2 and −1 and greater or equal than 0 for all other values. I really thought it was the other away around

Step-by-step explanation:

HOPE IT IS HELPFUL

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