answer this question 5 and 6
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5- Area of the enclosed figure PQRS =
1/2*(18+12)*14 = 210 cm^2.
6- Area enclosed by the given figure =
Area of rectangle ABEF + Area of triangle ECD + Area of triangle FHG =
(17*12)+2*30 = 264 cm^2.
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1/2*(18+12)*14 = 210 cm^2.
6- Area enclosed by the given figure =
Area of rectangle ABEF + Area of triangle ECD + Area of triangle FHG =
(17*12)+2*30 = 264 cm^2.
PLEASE MARK IT AS THE BRANLIEST.
YOU CAN ASK ME IF YOU HAVE ANY DOUBTS.
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