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Answer 1

Here,

It is given that ABC is a right anglrd isocsceles triangle

AC = BC

By Pythagoras Theorem

${AB}^{2} = {AC}^{2} + {BC}^{2} \\ {AB}^{2} = {4}^{2} + {4}^{2} \\ {AB}^{2} = 32 \\ AB= 4 \sqrt{2}$

Hope it helps you mate!!!!!

Answer 2

Answer:

Step-by-step explanation:

Right angle triangle

With Pythagoras theorm

AB square=BCsquare+CA square

16+16 = AB square

32 = AB square

AB = √32

AB= 4√2