Question

answer this question​

Answer 1

We will get x=3 by using basic proportionality theorem (bpt)

Answer 2

$\frac{ad}{db} = \frac{ae}{ec} \: \: by \: thales \: theorem \\ \frac{x + 1}{x - 1} = \frac{x + 3}{x} \\ {x}^{2} + x = {x}^{2} + 2x - 3 \\ x = 3$