Question

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Answer 1

Step-by-step explanation:

$it \: is \: given \\ \\ 3rd \: term = 5 \\ 7th \: term = 9$

$a + 2d = 5 \\ a + 6d = 9$

subtract both

$- 4d = - 4 \\ \: \: \: \: d = 1$

$a + 2 \times 1 = 5 \\ a = 3$

THEREFORE , AP = 3, 4 , 5 ,6 ........

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Answer 2

Answer:

3 , 4 , 5 , 6 , 7 , 8 , 9............

Step-by-step explanation:

an = a + (n-1)d

a3 = a + 2d = 5  ------- (1)

a7 = a + 6d = 9 -------- (2)

Subtract (1) from (2)

so,

4d = 4

d = 1

a3 = a + 2d = 5

a + 2 = 5

a = 3

a2 = a + d = 3 + 1 = 4

a4 = a + 3d = 3 + 3 = 6

similarly,

a5 = 7

a6 = 8

therefore, the required AP is

                   3 , 4 , 5 , 6 , 7 , 8 , 9............

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