Question

answer this question (c)

Answer 1

Let A(2,3) and B(6,-5) be intercepted by X-axis at point K(x,y)

1. Since the point is on X-axis, y=0 (i.e ordinate = 0)

2.

From the formula - The point which divides a line segment AB in the ratio m:n is given by [(mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n)] where A=(x₁,y₁),B=(x₂,y₂)

So, 0= [m(-5) + n(3)]/(m+n)

⇒ -5m + 3n = 0

⇒5m = 3n

⇒m:n = 3:5 is the ratio of divison of line AB

3.

Now x=[3(6) + 5(2)]/(3+5) = 28/8 = 3.5

So K= (3.5,0)

Answer 2

Let A(2,3) and B(6,-5) be intercepted by X-axis at point K(x,y)

1. Since the point is on X-axis, y=0 (i.e ordinate = 0)

2.

From the formula - The point which divides a line segment AB in the ratio m:n is given by [(mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n)] where A=(x₁,y₁),B=(x₂,y₂)

So, 0= [m(-5) + n(3)]/(m+n)

⇒ -5m + 3n = 0

⇒5m = 3n

⇒m:n = 3:5 is the ratio of divison of line AB

3.

Now x=[3(6) + 5(2)]/(3+5) = 28/8 = 3.5

So K= (3.5,0)

PLEASE MARK ME AS THE BRAINLIEST