Physics, asked by harshita046, 10 months ago

answer this question completely​

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Answers

Answered by sujithapg
0

Answer:

v²-u²=2as

distace = area under the graph

distance =area of triangle + area of rectangle

s =1/2bh+ LB

s=1/2*AC*AB+OD*DC

s=1/2*t*(v-u)+t*u

s=1/2*t*(v-u)+ ut

s=1/2vt +1/2ut

s=1/2t ( v+u)

s= 1/2(v-u)/a ( v+u)

s = 1/2a v²-u²

2as = v²-u²

v²-u²=2as

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Answered by Parulsinghal
32

Answer:

ok.. here is ur answer in the attachment ...

thank you

hope it helps ❤️❤️

plz mark it as brainliest...

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