Question

Answer this question correctly

Answer 1

Answer:

RTln2

MOLES n =1

Explanation:

FOR ISOBARIC PROCESS WORK DONE = P(V2–V1) = nR(T2–T1)

work done in AB, W1 = R (2T–T)= RT

work done in CD,W2 = R(T–2T)= –RT

FOR ISOTHERMAL PROCESS WORK DONE = nRTln(P1/P2)

work done in BC ,W3= R * 2T ln(2) = 2RTln2

work done in DA ,W4=R*T ln(1/2) = –RTln2

TOTAL WORK DONE = W1 + W2 + W3 + W4

TOTAL WORK = RTln2

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Answer 2

Answer:

Option(C)

Explanation:

(i)

$W_{AB} = nRdT$

$\Rightarrow 1 * R * (2T - T) = TR$

(ii)

$W_{BC} = nRT$

$\Rightarrow W_{BC} = R(2T) log 2$

(iii)

$W_{CA} = nRdT$

$\Rightarrow W_{CA} = -RT$

(iv)

$W_{DA} = nR + log(1/2)$

$\Rightarrow W_{DA} = RTlog2$

Now,

$W = \ W_{AB} + W_{BC} + W_{CA} + W_{DA}$

W = RT log 2

Hope it helps!