Question

answer this question correctly​

Answer 1

49 grams of H₂SO₄  in a system contains $3.011 * 10^{23}$ atoms.

Explanation:

49 gms of H₂SO₄ are present in a system.

1 mole of any compound has $6.022 * 10^{23}$ atoms.

To calculate the number of atoms in 49 gms of H₂SO₄, we calculate the moles;

$Moles\ = \frac{Given\ mass}{Molecular\ weight}$

[tex]Moles = \frac{49}{98}\\ Moles = 0.5\ moles[/tex]

Applying the unitary method.

1 mole = $6.022 * 10^{23}$ atoms.

0.5 mole = 0.5 * $6.022 * 10^{23}$ atoms.

0.5 mole = $3.011 * 10^{23}$ atoms.

Answer 2

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