Question

$\large \; {\underline{\underline{\pmb{\red{\frak{ \; Question \; :- }}}}}}$

$\dashrightarrow$ Three Cubes of Volume 64 cm³ are joined end to end . Find the Surfa e Area of Cuboid formed .



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$\large \; {\underline{\underline{\pmb{\pink{\frak{ \; Note \; :- }}}}}}$

$\longrightarrow$ $\red{\sf{ No \; Spams }}$
$\longrightarrow$ $\red{\sf{ Answer \; with \; Proper \; Explaination }}$



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Answer 1

$\large\underline{\bf{Solution}}$

$\small\underline{\sf{given \rightarrow three \: cubes \: each \: of \: {64cm}^{3} }}$

$\small{\sf{to \: find \rightarrow volume \: of \: cuboid}}$

$\large\underline{\sf{side^{3} = {64cm}^{3} }}$

$\large\underline{\sf{Side = \sqrt[3]{ {64cm}^{3} } }}$

$\large\underline{\sf{Side = 4cm}}$

$\large\underline{\sf{So \: the \: cuboid \: such \: formed}}$

$\large\underline{\sf{will \: have \downarrow}}$

$\large{\sf{length = 4cm \times 3}}$

$\large{\sf{12cm}}$

$\large{\sf{breadth = 4cm}}$

$\large{\sf{height = 4cm}}$

$\large{\sf{now \: we \: can \: use \: formula \: for}}$

$\large{\sf{volume \: of \: cuboid.}}$

$\large{\sf{volume_{cuboid} = l \times b \times h}}$

$\large{\sf{ \implies 12cm \times 4cm \times 4cm}}$

$\large{\sf{ \implies192 {cm}^{3} }}$

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$\large{\red{\mathfrak{note\rightarrow}}}\small{\sf{Scroll \: the \: screen \: for \: better \: experience}}$

Answer 2

Answer:

$\huge \dag \sf \red{question} \dashleftarrow$

Three Cubes of Volume 64 cm³ are joined end to end . Find the Surface Area of Cuboid formed .

$\huge \underline \mathbb \blue{{answer}} \downarrow$

Side of cube=a

Volume of cube= a³

$64 = {a}^{3} \\ \\ {(4)}^{3} = {a}^{3} \\ \\ \boxed{ \green{\bold{a = 4}}}$

Now, a=4cm

Length(l)=12cm

b=4cm

h=4cm

${ \underline{ \rule{200pt}{5pt}}}$

TSA of cuboid = 2(lb+bh+hl)

$= 2(12 \times 4 + 4 \times 4 + 4 \times 12) \\ \\ = 2(48 + 16 + 48) \\ \\ = 2 \times 112 \\ \\ = \boxed{ \large \sf \mathbb {\underline \pink {224cm}{ \pink{^{2}}}}}$

$\Large\textsf{Hope \: It \: Helped}$