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Let the angle be x
So its compliment = 90 - x
And its supplement = 180 - x
Given that the ratio of its compliment and supplement is 13 : 4
=> (180 - x) : (90 - x) :: 13 : 4
Product of extremes = Product of means
=> 4(180 - x) = 13(90 - x)
=> 720 - 4x = 1170 - 13x
=> 13x - 4x = 1170 - 720
=> 9x = 450°
=> x = 450/9
=> x = 50°
So your answer is option 2
Hope it helps dear friend ☺️
So its compliment = 90 - x
And its supplement = 180 - x
Given that the ratio of its compliment and supplement is 13 : 4
=> (180 - x) : (90 - x) :: 13 : 4
Product of extremes = Product of means
=> 4(180 - x) = 13(90 - x)
=> 720 - 4x = 1170 - 13x
=> 13x - 4x = 1170 - 720
=> 9x = 450°
=> x = 450/9
=> x = 50°
So your answer is option 2
Hope it helps dear friend ☺️
Answered by
12
Here is your solution
Given:-
The ratio of its compliment and supplement is 13 : 4
Let the angle be x
since compliment = 90 - x
its supplement = 180 - x
A/q
=> (180 - x) : (90 - x) :: 13 : 4
we know that
Product of extremes = Product of means.
=> 4(180 - x) = 13(90 - x)
=> 720 - 4x = 1170 - 13x
=> 13x - 4x = 1170 - 720
=> 9x = 450°
=> x = 450/9
=> x = 50°
2nd option is correct.
Hope it helps you
Given:-
The ratio of its compliment and supplement is 13 : 4
Let the angle be x
since compliment = 90 - x
its supplement = 180 - x
A/q
=> (180 - x) : (90 - x) :: 13 : 4
we know that
Product of extremes = Product of means.
=> 4(180 - x) = 13(90 - x)
=> 720 - 4x = 1170 - 13x
=> 13x - 4x = 1170 - 720
=> 9x = 450°
=> x = 450/9
=> x = 50°
2nd option is correct.
Hope it helps you
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