Question

Hii guys....good afternoon...plz give me solution of the below mentioned question ....ok thankyou....love you all friends...........










Q-A motorcyclist drives from place A to place B with a uniform speed of 30 km/h and returns from place B to place A with a uniform speed of 20 km/h . Find his average speed.

Answer 1

Let the distance between both places be x km.

Time taken during going = x/30. Hour
Time taken during returning = x/20.hour

Average speed = total distance travelled // total time taken.

= 2x//x/12
= 2x*12// x
= 24km/hr.

Hope that it will help you
If any doubt plz comment

Answer 2

$\huge\color{red}\fbox\textsf{ Hey Buddy }$

$\mathsf$Let the speed from point A to B = v = 30 km/h
Let the speed from point B to A = v' = 20 km/h

Now,

For Average speed we have;

$avg \: speed = \frac{2 \times v \times v'}{v + v'} \\ \\ = \frac{2 \times 30 \times 20}{20 + 30} \\ \\ = \frac{1200}{50} \\ \\ = 24 \: kmph$

/﹋\_
(҂`_´)
<,︻╦̵̵̿╤─ ҉ - - - - -Follow me- - - - - -
_/﹋\_