Question

find the x³ +y3+z3-3×y2 whe x=-2,y=-1and z=3

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Answer 1

Answer:

x3+y3+z3-3xy2=28

Step-by-step explanation:

x=2

y=-1

z=3

(2)^3+(-1),^3+(3)^3-3(2*(-1)^2

8-1+27-3(2)

7+27-6

7+21

28