answer this question fast and I don't want the value
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easy peasy.
CSA of Cylinder = 2*22/7*2.8*3.5 = 61.6 sq. cm
Slant Height of Cone = sqroot(h^2 + r^2) = 3.5 cm
Hence, CSA of Cone = 22/7*2.8*3.5 = 30.8 sq. cm
Total Area of 1 Tent = 61.6 + 30.8 = 92.4 sq. cm
Rate of Canvas = ₹120 per sq. metre
Number of Tents = 1500
Number of School to share the cost = 50
Hence, the amount contributed by each school = [1500/50]*[120*92.4] = ₹332640
Value - Humanitarian & Proactive efforts are shown by students and teachers :P
Hope this helps...
CSA of Cylinder = 2*22/7*2.8*3.5 = 61.6 sq. cm
Slant Height of Cone = sqroot(h^2 + r^2) = 3.5 cm
Hence, CSA of Cone = 22/7*2.8*3.5 = 30.8 sq. cm
Total Area of 1 Tent = 61.6 + 30.8 = 92.4 sq. cm
Rate of Canvas = ₹120 per sq. metre
Number of Tents = 1500
Number of School to share the cost = 50
Hence, the amount contributed by each school = [1500/50]*[120*92.4] = ₹332640
Value - Humanitarian & Proactive efforts are shown by students and teachers :P
Hope this helps...
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