Math, asked by pratapyash2004, 11 months ago

answer this question fast pls​

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Answered by kingofnewdays
1

Possible outcomes when three coins are tossed:

HHH

HHT

HTH

HTT

THH

THT

TTH

TTT

Winning chances :2/8

therefore losing chances:6/8=3/4

Answered by AdarshAbrahamGeorge
1

Answer:

 \frac{3}{4}

Step-by-step explanation:

Possible outcomes = {(H,H,H) (H,H,T) (H,T,H) (T,H,H) (T,T,H)(T,H,T) (H,T,T) (T,T,T)}

No: of Outcomes = 8

No: of Outcomes that favours him to win the game = 2

>>> No: of Outcomes that results in him losing the game

= 8 - 2

= 6

P(Loses the game)

= 6/8

= 3/4

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