Question

Answer this question fastly it's very urgent

Answer 1

the area of quadrilateral is area of triangle PQS+SQR
i.e 1/2*12*9+1/2*17*8
i.e 6*9+17*4
. 54+68
. 122cmsq.

Answer 2

Hey Mate,

Given,

∠QPS = ∠SQR = 90 degrees.

PQ = 12 cm

PS = 9 cm

QR = 8 cm

SR = 17 cm

From this information, we can infer that the quadrilateral PQRS is made up of 2 right - angled triangles.

Hence, Area of Quadrilateral PQRS = Area of Triangle PQS + Area of Triangle QRS

Area of a Triangle = 1/2 x Base x Height

Area of Triangle PQS = 1/2 x 12 x 9

Area of Triangle PQS = 54 sq. cm

Now, Area of Triangle QRS also = 1/2 x Base x Height

Area of Triangle QRS = 1/2 x 8 x 17

Area of Triangle QRS = 68 sq. cm

Since, Area of Quadrilateral PQRS = Area of Triangle PQS + Area of Triangle QRS

Area of Quadrilateral PQRS = 54 + 68

Area of Quadrilateral PQRS = 122 sq. cm

Therefore, Area of Quadrilateral PQRS = 122 sq. cm.

Hope it Helps!