Question

answer this question frnds❤️

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Answer 1

Answer:

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Answer 2

$\sf\color{lime}{Figure}$

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\linethickness{0.4mm}\put(7.7,3){\large\sf{A}}\put(7.6,2){\sf{\large{x}}}\put(7.7,1){\large\sf{B}}\put(9.2,0.7){\sf{\large{(x + 7)}}}\put(11.1,1){\large\sf{C}}\put(11.1,3){\large\sf{D}}\put(8,1){\line(1,0){3}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\end{picture}$

$\huge\sf\pink{Answer}$

☞ Length of the rectangle = 12 cm

☞ Breadth = 5 cm

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$\huge\sf\blue{Given}$

➢ Length of a rectangle exceeds the width by 7 cm

➢ Area = 60 cm²

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$\huge\sf\gray{To\:Find}$

➳ Length and breath?

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$\huge\sf\purple{Steps}$

Let the width of rectangle be x and length of rectangle be (x + 7) respectively.

❍ $\underline{\sf{According\: to \:the\: Question\:now :}}$

$\longmapsto\sf Area_{(Rectangle)}=Length \times Width\\\\ \longmapsto\sf 60 = (x + 7) \times x\\\\ \longmapsto\sf 60 = x^2 + 7x\\\\ \longmapsto\sf x^2 + 7x - 60 = 0\\\\ \longmapsto\sf x^2 + (12-5)x - 60 = 0\\\\ \longmapsto\sf x^2 + 12x - 5x - 60 = 0\\\\ \longmapsto\sf x(x + 12) - 5(x + 12) = 0\\\\ \longmapsto\sf (x - 5)(x + 12) = 0\\\\ \longmapsto\color{aqua}{\sf x = 5} \quad \sf\color{black}{ or} \quad \color{red}{x = - \:12}$

✭ Ignoring Negative , width be x = 5

❍ $\underline{\sf{Dimensions\: of \:the\: Rectangle :}}$

$\bullet\:\:\textsf{Length = (x + 7) = \orange{12 cm}}\\\bullet\:\:\textsf{Width = x = \green{5 cm}}$

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