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a
2
−2ab+b
2
−c
2
=(a−b)
2
−c
2
(∵(x−y)
2
=x
2
−2xy+y
2
)
=(a−b+c)(a−b−c)(∵x
2
−y
2
=(x−y)(x+y))
Answered by
1
Step by step explanation:
(a-b)²-c²
[(a-b-c)(a-b+c)]
(a-b-c)(a-b+c) -------------{required factorisation}
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