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If BC passes through the centre of the circle, then the area of the shaded region in the given figure is :
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HELLO DEAR,
IN∆ABC ,<A=90°
[ any triangle drawn on diameter of a Circle are right triangle]
(BC)² = (AB)² + (AC)²
=> BC² = a²+a²
=> BC = a√2 = diameter of Circle
=> radius if Circle = a√2/2
area of semicircle = 1/2πr²
=> 1/2×(π×a²×2/4) = πa²/4
AND,
area of ∆ABC
=> 1/2 × AB × AC
=> 1/2 ×a × a
=> a² ×1/2unit²
area of shaded region = area of semicircle - area of triangle ABC
=> πa²/4 - a²/2
=> a²/2 (π/2 - 1)
hence, option (D) IS CORRECT
I HOPE ITS HELP YOU DEAR,
THANKS
IN∆ABC ,<A=90°
[ any triangle drawn on diameter of a Circle are right triangle]
(BC)² = (AB)² + (AC)²
=> BC² = a²+a²
=> BC = a√2 = diameter of Circle
=> radius if Circle = a√2/2
area of semicircle = 1/2πr²
=> 1/2×(π×a²×2/4) = πa²/4
AND,
area of ∆ABC
=> 1/2 × AB × AC
=> 1/2 ×a × a
=> a² ×1/2unit²
area of shaded region = area of semicircle - area of triangle ABC
=> πa²/4 - a²/2
=> a²/2 (π/2 - 1)
hence, option (D) IS CORRECT
I HOPE ITS HELP YOU DEAR,
THANKS
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