Question

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Answer 1

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Answer 2

$tan \: 30 \degree = \frac{1}{ \sqrt{3} }$

$tan \: 45 \degree = 1$

Putting in the equation we get,

=$\frac{2 \times \frac{1}{ \sqrt{3} } }{1 + 1}$

=$\frac{2}{ \sqrt{3} } \times \frac{1}{2}$

=$\frac{2}{2 \sqrt{3} } \:$

=$\frac{1}{ \sqrt{3} }$

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