answer this question no.9
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Answer:
24°, 72°, 48°
Step-by-step explanation:
In cyclic quadrilateral ABCE,
∠ABC + ∠AEC = 180°
⇒ 132 + ∠AEC = 180°
⇒ ∠AEC = 48°
(i)
∠AEB = (1/2) * ∠AEC
= (1/2) * 48
= 24°.
So, ∠AEB = ∠BEC = ∠CED = 24°.
(ii)
∠AED = ∠AEB + ∠BEC + ∠CED
= 24 + 24 + 24
= 72°.
(iii)
∠COD = 2 * ∠CED
= 2 * 24
= 48°.
Hope it helps!
lenovok5pk:
thanks bhai
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