Math, asked by lenovok5pk, 10 months ago

answer this question no.9

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Answers

Answered by siddhartharao77
7

Answer:

24°, 72°, 48°

Step-by-step explanation:

In cyclic quadrilateral ABCE,

∠ABC + ∠AEC = 180°

⇒ 132 + ∠AEC = 180°

⇒ ∠AEC = 48°

(i)

∠AEB = (1/2) * ∠AEC

          = (1/2) * 48

          = 24°.


So, ∠AEB = ∠BEC = ∠CED = 24°.


(ii)

∠AED = ∠AEB + ∠BEC + ∠CED

          = 24 + 24 + 24

          = 72°.


(iii)

∠COD = 2 * ∠CED

           = 2 * 24

           = 48°.



Hope it helps!


lenovok5pk: thanks bhai
lenovok5pk: apka konsa class
Anonymous: age 21 class ??? class 12 in 17 years so 21 years = class12+4 = clas16
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