Question

Answer this Question of iit jee .
Chapter → Electrostatics​​

Answer 1

At P, potential due to shell

$V_ 1 = \frac{q}{4\pi \: E_oR}$

At P, potential due to Q

$v_ 2 = \frac{Q}{4\pi E_o \frac{R}{2} }$

$\therefore \: net \: potential \: at \: P$

$V = V_1 + V_2$

$v = \frac{q}{4\pi \: E_o \: R} + \frac{2Q}{4\pi \: E_o \: {R} }$

Option C) is correct