Question

answer this question (only for class 10th )

Answer 1

Let the fixed charge for first three days and each day charge thereafter be Rs x and Rs y respectively.According to the question,x + 4y = 27 ... (i)x + 2y = 21 ... (ii)Subtracting equation (ii) from equation (i), we get2y = 6y = 3 ... (iii)Putting in equation (i), we getx + 12 =27x = 15Hence,fixed charge = Rs 15 and Charge per day = Rs 3.
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Hope it helps u so marks it as a brainliest answer

Answer 2

Hey your answer is here!!!!!!!!!!!!!!!!!!!

Let to be Fixed charge be X
the charge of each extra be Y

therefore,
In case of saritha, equation will be formed.

x+4y=27

In case of Susy, equation will be formed

X+2y=21
by elimination method.......

x+4y=27
x+2y=21
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2y=6
y=6/2
Y=3
...
Now you can put on another equation
X+2(3)=21
x+6=21
X=21-6
X=15

so fixed charge value =15 and extra each charge=3..….