Question

answer this question please​

Answer 1

Hey frnd here is your answer

Now mark my answer as brainliest answer

Answer 2

Hey mate_____❤️❤️


Answer:-
Since the given points A(3k-1,k-2) ,B(k,k-7) and C(k-1,-k-2) are collinear the area of triangle formed by them is 0

=>1/2[(3k-1)(k-7+k+2)+(k)(-k-2-k+2)+(k-1)(k-2-k+7)]=0
=>[(3k-1)(2k-5)+(k)(-2k)+(k-1)(5)]=0
=>6k^2-17k+5-2k^2+5k-5=0
=>4k^2-12k=0
=>4k(k-3)=0

4k=0. |. k-3=0
k=0. |. k=3





hope it will help uh