Chemistry, asked by scarlet63, 5 months ago

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Answered by diajain01
8

ANSWER⤵️

for isothermal process,

triangle E = 0

w= -2.303nRTlog10. P1/P2

w= -2.303×1×2×300×log2/10

w= +2.303×600×log5

w= 2.303×600×0.699

w= +965.87Cal

For isothermal process

w= -q

q= -965.87 cal

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Answered by Anonymous
7

for isothermal process,

triangle E = 0

w= -2.303nRTlog10. P1/P2

w= -2.303×1×2×300×log2/10

w= +2.303×600×log5

w= 2.303×600×0.699

w= +965.87Cal

For isothermal process

w= -q

q= -965.87 cal

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