Math, asked by nel10, 1 year ago

answer this question pls​

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Answered by siddhartharao77
9

Step-by-step explanation:

Total number of die thrown = 2.

Possible outcomes, n(S) = 36.

(i) 5 will not come up either time:

A = {1,1},{1,2},{1,3},{1,4},{1,6},{2,1},{2,2},{2,3},{2,4],{2,6},{3,1},{3,2},{3,3},{3,4},{3,6},{4,1},{4,2},{4,3},{4,4},{4,6},{6,1},{6,2},{6,3},{6,4},{6,6}

n(A) = 25.

Required probability P(A) = n(A)/n(S)

                                          = 25/36

(ii) 5 will come up at least once:

B = {1,5}, {2,5},{3,5},{4,5},{5,5},{6,5},{5,1},{5,2},{5,3},{5,5},{5,6}

n(B) = 11

Required probability P(B) = n(B)/n(S)

                                          = 11/36.

Hope it helps!

Answered by rachitsainionline
0

Step-by-step explanation:

Total number of die thrown = 2.

Possible outcomes, n(S) = 36.

(i) 5 will not come up either time:

A = {1,1},{1,2},{1,3},{1,4},{1,6},{2,1},{2,2},{2,3},{2,4],{2,6},{3,1},{3,2},{3,3},{3,4},{3,6},{4,1},{4,2},{4,3},{4,4},{4,6},{6,1},{6,2},{6,3},{6,4},{6,6}

n(A) = 25.

Required probability P(A) = n(A)/n(S)

                                          = 25/36

(ii) 5 will come up at least once:

B = {1,5}, {2,5},{3,5},{4,5},{5,5},{6,5},{5,1},{5,2},{5,3},{5,5},{5,6}

n(B) = 11

Required probability P(B) = n(B)/n(S)

                                          = 11/36.

Hope it helps!

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