Question

answer this question plxx​

Answer 1

$\huge{\mathtt{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}\blue{!}}}$

Given:

R=3cm, H=10.5cm

⇒Surface area = Curved Surface Area + Base Area

=2πrh+πr²

$= 2 \times \frac{22}{7} \times 3 \times \frac{10.5}{10} + \frac{22}{7} \times 3 \times {3cm}^{2} \\ \\ = 198 + \frac{198}{7} {cm}^{2} \\ \\ = \frac{1584}{7} {cm}^{2}$

$area \: of \: cardboard \: sheet \: used \: by \: competitors = \frac{1584}{7} {cm}^{2} \\ \\ area \: of \: cardboard \: sheet \: used \: by \: 35 \: competitors = \frac{1584}{ \cancel{7}} \times \cancel{35} \\ \\ = {7920 \: cm}^{2}$

Answer 2

Answer:

Given:

R=3cm, H=10.5cm

⇒Surface area = Curved Surface Area + Base Area

=2πrh+πr

2

=2×

7

22

×3×

10

10.5

+

7

22

×3×3cm

2

=198+

7

198

cm

2

=

7

1584

cm

2

⇒Area of cardboard sheet used by competitor =

7

1584

cm

2

⇒Area of cardboard sheet used by 35 competitors =

7

1584

×35

=7920cm

2