Question

Answer this question plzzz....​

Answer 1

Answer:

By dividing numerator and denominator by sinA you will get the answer definetly.

Answer 2

Step-by-step explanation:

solution----->

Given:-

$\frac{1 - cos \: a}{1 + cos \: a} = ( {cot \: a - cosec \: a)}^{2} \\ \\ now \: take \\ \\ lhs = \frac{1 - cos \: a}{1 + cos \: a} \\ \\ now \: multiply \: with \: (1 - cos \: a) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1 - cos \: a}{1 + cos \: a} \times \frac{1 - cos \: a}{1 - cos \: a}\\ \\ \: \: \: \: \: \: \: \: \: = \frac{ {(1 - cos \: a)}^{2} }{1 - {cos \: a}^{2} } \\ \\ \: \: \: \: \: \: \: = \frac{ {(1 - cos \: a)}^{2} }{ {sin \: a}^{2} } \\ \\ becoz \: of \:1 - {cos \: a }^{2} = {sin \: a}^{2} \\ \\ \: \: \: \: \: \: \: = ({ \frac{1 - cos}{sin} )}^{2} \\ \\ \: \: \: \: \: \: \: = ( { \frac{1}{sin} - \frac{cos}{sin} })^{2} \\ \\ as \: we \: know \\ \\ \frac{1}{sin \: } = cosec \: a \\ \\ \frac{cos \: a}{sin \: a} = cot \: a \\ \\ \: \: \: \: \: \: \: \: =( {cosec \: a \: - cot \: a})^{2} \\ \\ hence \: its \: prove.....$