Physics, asked by mohit1315, 1 year ago

answer this question with explanation

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Answered by Somin

It is the universal law of gravitation that

F = G Mm/R2

So when the radius of the earth is reduced than acceleration due to gravity (gravitational force exerted by earth) will increase as Radius and the force are inversely proportional to each other.

AmritaD: Its asked 'acceleration due to gravity'. Not 'Gravitational constant'. Both have a huge difference. Your answer is incorrect.

Somin: Acceleartion due to gravity is the force by which earth attracts an object towards it

Somin: It means that right?

Somin: And acceleration due to gravity is calculated by the universal gravitational constant of F= Gmm/dw

AmritaD: g = Gm/R²

Somin: Isn't it generated fron universal constant?

Somin: When we take F= mg

Somin: Then the formual relatively becomes mg= GMm/R2

Somin: g = GM/R2

Answered by AmritaD

The acceleration due to gravity is a kind of acceleration. And we know acceleration = metre/second². The acceleration due to gravity in the surface of earth is g = Gm/R².
We know, the force of gravity at the Earth’s surface would increase slightly as it is inversely proportional to the square of the distance between two masses. If you decrease that distance to 99%, then everybody’s weight (and the acceleration due to gravity) would increase by (approximately) 2.03%.
So your answer is option C. Increase.

Hope the explanation helps. Thank you. ☺♥

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