Question

answer this question with explanation​

Answer 1

Answer:

(a). √(  $\frac{x-1}{x+1}$ )

Step-by-step explanation:

sin²A + cos²A = 1

cos²A = 1 - $\frac{x-1}{2x}$ = $\frac{2x-x+1}{2x}$ = $\frac{x+1}{2x}$

sin²A = $\frac{x-1}{2x}$

$\frac{sin^2A}{cos^2A}$ = tan²A = $\frac{x-1}{2x}$ ÷ $\frac{x+1}{2x}$ = $\frac{x-1}{x+1}$

tan A = √(  $\frac{x-1}{x+1}$ )