Question

answer this question with full explanation ​

Answer 1

Answer:

in my opinion c) 2a (answer)

Answer 2

Answer:

• Option (d)

Solution:

There are two points given in the question as P(a sin Φ, 0) and Q(0, - a cos Φ) and we have to find the distance between these two points.

As we have studied earlier, the distance between two points (x₁ , y₁) and (x₂ , y₂) is given by the following formula:

• √{ (x₂ - x₁)² + (y₂ - y₁)² }

Comparing given points with the general expression of the two points i.e., (x₁ , y₁) and (x₂ , y₂), we have

• x₁ = a sin Φ
• y₁ = 0
• x₂ = 0
• y₂ = -a cos Φ

Now, substituting the required values in the formula, we get

=> √{ (0 - a sin Φ)² + (-a cos Φ - 0)² }

=> √{ (-a sin Φ)² + (-a cos Φ)² }

=> √( a²sin²Φ + a²cos²Φ )

=> √{ a² ( sin² Φ + cos² Φ ) }

=> √{ a² (1) }

Since, sin² Φ + cos² Φ = 1,

=> √( a² )

=> a

So, The distance between the two points is a units.

Therefore, Option (D) is correct.