Question

Answer this question with full solution

Answer 1

hwy mate :-

given here

a+b=10. ...(1)

a²+b²=58. ...(2)

find here

a³+b³=?

Solution:-

we know that

(x+y)²=x²+y²+2xy

so,

(a+b)²=a²+b²+2ab

put value by (1) and (2)

(10)²=58+2ab

100-58=2ab

42=2ab

ab = 42/2

ab = 21. .....(3)

again we known

x³+y³=(x+y)(x²+y²-xy)

so,

a³+b³=(a+b)(a²+b²-ab)

put value by (1) ,(2)and (3)

we get ...

a³+b³=(10)(58-21)

=(10)(37)

=370

I hopes its help's u

please follow me ...✌✌

@Abhi.❤❤

Answer 2

hwy mate :-

given here

a+b=10. ...(1)

a²+b²=58. ...(2)

find here

a³+b³=?

Solution:-

we know that

(x+y)²=x²+y²+2xy

so,

(a+b)²=a²+b²+2ab

put value by (1) and (2)

(10)²=58+2ab

100-58=2ab

42=2ab

ab = 42/2

ab = 21. .....(3)

again we known

x³+y³=(x+y)(x²+y²-xy)

so,

a³+b³=(a+b)(a²+b²-ab)

put value by (1) ,(2)and (3)

we get ...

a³+b³=(10)(58-21)

=(10)(37)

=370

I hopes its help's u

please follow me ...✌✌

@Abhi.❤❤