Question

Answer this question with solution ​

Answer 1

Answer:

area of ∆PQR=1/2×PQ×QR

60=1/2×8×QR=QR=60×2/8

QR=15

in right angle ∆PQR

PR^2=PQ^2+QR^2

PR^2=8^2+15^2=64+225

PR^2=289=PR=√289=17cm