Question

Answer this question with Solution please

Answer 1

According to the question,

Jack took 10 5/11 min = 115/11 min

Jill took 13 3/7 min = 94/7 min

NOW WE SHALL COMAPRE BOTH THE FRACTIONS ;

by making their denominators equal i.e. 77 which is LCM of 11 and 7.

$\frac{115}{11} = \frac{805}{77} \\ \\ \frac{94}{7} = \frac{1034}{77} \\ \\ \frac{1034}{77} > \frac{805}{77} \implies \frac{94}{7} > \frac{115}{11}$

Therefore, Jill took more time to complete the assignment.

The difference between the time taken by Jill and Jack is;

$\frac{94}{7} - \frac{115}{11} \\ \\ = \frac{(1034 - 807)}{77} \\ \\ = \boxed{ \frac{227}{77} } \\ \\ \boxed{2.94min}$

Therefore Jill 2.94min more than Jack to complete the assignment. [Ans]