Question

answer this questions​

Answer 1

1).

17^ 0 = 1

Any integer whose power is 0 becomes 1 .

Therefore.,. This can be expressed as .

(1+1)(1-1)(1+2)

= 0

2). {(6/7)²-⁴}(6/7)^5

(6/7)³

216/ 343

Answer 2

$(iii) \: [{17}^{0} + {18}^{0}] [ {19}^{0} - {22}^{0} ] [{23}^{0} + {2(24)}^{0} ]\\ \\ =( 1 + 1) (1 - 1)(1 + 2 \times 1) \\ \\ = 2 \times 0 \times 3 \\ \\ = \boxed 0(ans)$

$(iv){[(\frac{6}{7})}^{2} \div {(\frac{6}{7})}^{4}] \times {(\frac{6}{7})}^{3} \\ \\ = {(\frac{6}{7})}^{2 - 4} \times {(\frac{6}{7})}^{3} \\ \\ = {(\frac{6}{7})}^{ - 2} \times {(\frac{6}{7})}^{3} \\ \\ = \boxed {\frac{6}{7}}$

RULES USED ABOVE :-

${a}^{0} = 1 \\ \\ \frac{ {a}^{b} }{ {a}^{c} } = {a}^{b - c} \\ \\ {a}^{b} \times {a}^{c} = {a}^{b + c}$